A solid ball of density half that of water falls freely under gravity from a height of 19.6 m and then enters water. How much time will it take to come again to the water surface? Neglect air resistance and viscosity effects in water. (Take, 
)
Text Solution
Verified by ExpertsThe correct answer is:
A
Velocity under free fall
Let 
be the density of ball and 
the density of water. Net retardation inside the water,
Hence, the ball will go upto the same depth 19.6 m below the water surface. Further, time taken by the ball to come back to water surface is
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